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NCERT Chemistry Class 11 - Chapter 7: Redox Reactions - Notes

CBSEClass 11Chemistryअपचयोपचय अभिक्रियाएँ

Learning Objectives

  • Understand oxidation, reduction, and redox reactions
  • Learn to assign oxidation numbers (states)
  • Balance redox equations using ion-electron and oxidation number methods
  • Classify redox reactions into different types
  • Understand electrochemical cells and their relation to redox

Key Concepts

Oxidation and Reduction

Classical definition: Oxidation = gain of oxygen / loss of hydrogen. Reduction = loss of oxygen / gain of hydrogen.

Electronic concept: Oxidation = loss of electrons. Reduction = gain of electrons.

Oxidation number concept: Oxidation = increase in oxidation number. Reduction = decrease in oxidation number.

Oxidation and reduction always occur simultaneously (redox reactions). The substance oxidised is the reducing agent; the substance reduced is the oxidising agent.

Rules for Assigning Oxidation Numbers

  • Free elements: 0 (e.g., Na, O₂, S₈).
  • Monoatomic ions: equal to charge (Na⁺ = +1, Cl⁻ = -1).
  • Hydrogen: +1 (except metal hydrides: -1, e.g., NaH).
  • Oxygen: -2 (except peroxides: -1, superoxides: -½, OF₂: +2).
  • Fluorine: always -1.
  • Sum of oxidation numbers = 0 (neutral molecule) or charge (for ions).

Types of Redox Reactions

  • Combination: A + B → AB (e.g., 2Mg + O₂ → 2MgO)
  • Decomposition: AB → A + B (e.g., 2H₂O → 2H₂ + O₂)
  • Displacement: A + BC → AC + B (e.g., Zn + CuSO₄ → ZnSO₄ + Cu)
  • Disproportionation: Same element is both oxidised and reduced (e.g., 2H₂O₂ → 2H₂O + O₂, where O goes from -1 to -2 and 0).
  • Comproportionation: Same element in two different oxidation states combine to form a single oxidation state.

Balancing Redox Equations

Oxidation Number Method:

  1. Assign oxidation numbers to all atoms.
  2. Identify atoms whose oxidation numbers change.
  3. Calculate increase and decrease in oxidation number.
  4. Equalise total increase and decrease.
  5. Balance remaining atoms (H and O).

Ion-Electron (Half-Reaction) Method:

  1. Split into oxidation and reduction half-reactions.
  2. Balance atoms other than H and O.
  3. Balance O by adding H₂O (acidic) or OH⁻ (basic).
  4. Balance H by adding H⁺ (acidic) or H₂O (basic).
  5. Balance charge by adding electrons.
  6. Equalise electrons and add half-reactions.

Redox Reactions and Electrode Processes

Electrochemical cells convert chemical energy to electrical energy (galvanic cells) or vice versa (electrolytic cells).

Oxidation occurs at anode (-ve in galvanic). Reduction at cathode (+ve in galvanic).

Activity series determines which metal displaces another from solution.

Summary

Redox reactions involve simultaneous oxidation and reduction, tracked by changes in oxidation numbers. The oxidising agent is reduced (gains electrons); the reducing agent is oxidised (loses electrons). Redox equations are balanced by the oxidation number method or ion-electron method. Disproportionation involves the same element being both oxidised and reduced. Electrochemical applications connect redox chemistry to electricity.

Important Terms

  • Oxidation Number: Hypothetical charge on an atom if all bonds were ionic
  • Oxidising Agent: Accepts electrons, gets reduced
  • Reducing Agent: Donates electrons, gets oxidised
  • Disproportionation: Same species undergoes both oxidation and reduction
  • Half-Reaction: Oxidation or reduction part of a redox reaction

Quick Revision

  • Oxidation: loss of electrons, increase in oxidation number
  • Reduction: gain of electrons, decrease in oxidation number
  • O.N. rules: H = +1 (except hydrides -1), O = -2 (except peroxides -1)
  • Oxidising agent gets reduced; Reducing agent gets oxidised
  • Balance by: oxidation number method or ion-electron method
  • Disproportionation: H₂O₂, Cl₂ in NaOH, P₄ in NaOH
NCERT Chemistry Class 11 - Chapter 7: Redox Reactions - Notes | EduMunch