NCERT Physics Class 11 - Chapter 14: Oscillations - Notes

दोलन

Learning Objectives

  • Understand periodic, oscillatory, and simple harmonic motion
  • Derive equations for displacement, velocity, and acceleration in SHM
  • Study energy in SHM and its oscillation between KE and PE
  • Learn about the simple pendulum and spring-mass system
  • Understand damped, forced oscillations, and resonance

Key Concepts

Simple Harmonic Motion (SHM)

A periodic motion where the restoring force is directly proportional to displacement from the mean position and is directed towards it.

Condition: F = -kx (Hooke's law type restoring force)

Differential equation: d²x/dt² + ω²x = 0

Equations of SHM

Displacement: x(t) = A sin(ωt + φ) or x(t) = A cos(ωt + φ)

Velocity: v(t) = Aω cos(ωt + φ) = ω√(A² - x²)

Acceleration: a(t) = -Aω² sin(ωt + φ) = -ω²x

Maximum velocity: v_max = Aω (at mean position). Maximum acceleration: a_max = Aω² (at extreme position).

where A = amplitude, ω = angular frequency, φ = initial phase, (ωt + φ) = phase.

Time period: T = 2π/ω. Frequency: f = 1/T = ω/2π.

Energy in SHM

Kinetic Energy: KE = ½mω²(A² - x²) = ½mω²A² cos²(ωt + φ)

Potential Energy: PE = ½mω²x² = ½mω²A² sin²(ωt + φ)

Total Energy: E = KE + PE = ½mω²A² = ½kA² = constant

KE and PE oscillate with frequency 2ω (twice the SHM frequency). Average KE = Average PE = E/2.

At mean position: KE = max, PE = 0. At extremes: KE = 0, PE = max.

Spring-Mass System

Time period: T = 2π√(m/k), ω = √(k/m)

Independent of amplitude and acceleration due to gravity.

Springs in series: 1/k_eff = 1/k₁ + 1/k₂

Springs in parallel: k_eff = k₁ + k₂

Simple Pendulum

Time period: T = 2π√(L/g) (for small angular amplitude θ < 15°)

Independent of mass and amplitude (for small oscillations).

Restoring force: F = -mg sin θ ≈ -mgθ (for small θ)

Effective length L = distance from pivot to centre of mass of bob.

In an accelerating lift: T = 2π√(L/g_eff), where g_eff = g + a (upward) or g - a (downward).

Damped Oscillations

Oscillations whose amplitude decreases over time due to resistive forces (like friction, air resistance).

Equation: x(t) = Ae^(-bt/2m) sin(ω't + φ), where b is the damping constant.

Damped frequency: ω' = √(ω₀² - (b/2m)²) < ω₀ (natural frequency).

Energy: E(t) = ½kA²e^(-bt/m) (exponential decay).

Forced Oscillations and Resonance

When an external periodic force drives the oscillation: F_ext = F₀ cos ωdt

Resonance: When driving frequency ωd equals natural frequency ω₀, amplitude is maximum. This is resonance.

Amplitude at resonance: A_max = F₀/(bω₀) (limited by damping).

Applications: tuning a radio, musical instruments, swinging, MRI.

Summary

SHM is characterized by a restoring force proportional to displacement. The displacement, velocity, and acceleration are sinusoidal functions. Total energy in SHM is constant and proportional to A². The simple pendulum (T = 2π√(L/g)) and spring-mass system (T = 2π√(m/k)) are classic examples. Damped oscillations lose energy over time. Forced oscillations at resonance produce maximum amplitude.

Important Terms

  • Amplitude: Maximum displacement from mean position
  • Phase: Argument of the sinusoidal function, determines position at any time
  • Angular Frequency: ω = 2π/T = 2πf
  • Resonance: Maximum amplitude when driving frequency equals natural frequency
  • Damping: Decrease in amplitude due to dissipative forces

Quick Revision

  • SHM: x = A sin(ωt + φ), v = Aω cos(ωt + φ), a = -ω²x
  • v_max = Aω (at x=0); a_max = Aω² (at x=±A)
  • E = ½kA² = ½mω²A² = constant
  • Spring: T = 2π√(m/k); Pendulum: T = 2π√(L/g)
  • At mean position: KE = max, PE = 0
  • Resonance: ωd = ω₀ → maximum amplitude
NCERT Physics Class 11 - Chapter 14: Oscillations - Notes | EduMunch