NCERT Physics Class 12 - Chapter 2: Electrostatic Potential and Capacitance - Notes

स्थिरवैद्युत विभव तथा धारिता

Learning Objectives

  • Define electrostatic potential and potential difference
  • Calculate potential due to various charge configurations
  • Understand equipotential surfaces and their properties
  • Learn about capacitors, capacitance, and their combinations
  • Study energy stored in capacitors and effect of dielectrics

Key Concepts

Electric Potential

Electric potential at a point: V = W/q₀ = kQ/r (work done per unit positive charge in bringing it from infinity).

SI unit: volt (V) = J/C. It is a scalar quantity.

Potential difference: V_A - V_B = W_AB/q₀ (work done in moving unit charge from B to A).

Relation to field: E = -dV/dr. The electric field points in the direction of decreasing potential.

Potential Due to Charge Configurations

Point charge: V = kq/r

System of charges: V = k Σ(qᵢ/rᵢ) (scalar addition)

Dipole (axial): V = kp cos θ/r² (for r >> a)

Uniformly charged sphere (outside): V = kQ/r; (on surface): V = kQ/R; (inside): V = kQ(3R² - r²)/(2R³)

Equipotential Surfaces

Surfaces where potential is the same at every point. No work is done in moving a charge along an equipotential surface.

Properties: perpendicular to electric field lines, never intersect, closer together where field is stronger.

For a point charge: concentric spheres. For uniform field: parallel planes.

Electrostatic Potential Energy

Two-charge system: U = kq₁q₂/r

Three-charge system: U = k(q₁q₂/r₁₂ + q₂q₃/r₂₃ + q₁q₃/r₁₃)

Charge in external field: U = qV(r)

Capacitance

C = Q/V (charge stored per unit potential difference). SI unit: farad (F).

Parallel plate capacitor: C = ε₀A/d (A = plate area, d = separation).

With dielectric (κ): C = κε₀A/d = κC₀.

Spherical capacitor: C = 4πε₀(ab)/(b - a) (for inner radius a, outer radius b).

Cylindrical capacitor: C = 2πε₀L/ln(b/a).

Combination of Capacitors

Series: 1/C_eq = 1/C₁ + 1/C₂ + ... (same charge, voltage divides).

Parallel: C_eq = C₁ + C₂ + ... (same voltage, charge divides).

Energy Stored in a Capacitor

U = ½CV² = ½QV = Q²/(2C)

Energy density: u = ½ε₀E² (energy per unit volume in the electric field).

Effect of Dielectric

Inserting a dielectric (κ > 1) between plates:

  • With battery connected: V stays same, C increases (κC₀), Q increases, E stays same
  • With battery disconnected: Q stays same, C increases (κC₀), V decreases (V₀/κ), E decreases (E₀/κ)

Summary

Electric potential is a scalar quantity representing potential energy per unit charge. Equipotential surfaces are perpendicular to field lines. Capacitance measures the ability to store charge. Parallel plate capacitance depends on area, separation, and dielectric. Capacitors combine in series (reciprocal addition) and parallel (direct addition). Energy stored is ½CV². Dielectrics increase capacitance by factor κ.

Important Terms

  • Electric Potential: Work done per unit charge from infinity, V = kQ/r
  • Equipotential Surface: Surface of constant potential
  • Capacitance: Ability to store charge, C = Q/V
  • Dielectric: Insulating material that increases capacitance
  • Dielectric Constant (κ): Factor by which capacitance increases with dielectric
  • Energy Density: Energy stored per unit volume, u = ½ε₀E²

Quick Revision

  • V = kQ/r; E = -dV/dr
  • C = ε₀A/d (parallel plate); C = κε₀A/d (with dielectric)
  • Series: 1/C = 1/C₁ + 1/C₂; Parallel: C = C₁ + C₂
  • U = ½CV² = ½QV = Q²/2C
  • Energy density: u = ½ε₀E²
  • Dielectric with battery off: Q same, V ↓, C ↑; with battery on: V same, Q ↑, C ↑
NCERT Physics Class 12 - Chapter 2: Electrostatic Potential and Capacitance - Notes | EduMunch